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Question 9.9

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TZ
leumasicOfficial

3 months ago

i) Let g(x)=x5g(x)=x^5. We know that g(x)=5x4g'(x)=5x^4 by Exercise 4 of this chapter. Hence, we can write

f(x)=g(x+3)=(x+3)5f(x)=g(x+3)=(x+3)^5

and

f(x)=g(x+3)=5(x+3)4f'(x)=g'(x+3)=5(x+3)^4

by Exercise 8a). This also means that

f(x+3)=5(x+6)4.f'(x+3)=5(x+6)^4.

ii) Let z=x+3z=x+3. Then x=z3x=z-3 and

f(x+3)=f(z)=(z3)5.f(x+3)=f(z)=(z-3)^5.

By the same argument as in i), we have

f(z)=5(z3)4f'(z)=5(z-3)^4

and

f(z+3)=5z4.f'(z+3)=5z^4.

iii) Let z=x+3z=x+3. Then x=z3x=z-3 and

f(x+3)=f(z)=(z+2)7.f(x+3)=f(z)=(z+2)^7.

It follows that

f(z)=7(z+2)6f'(z)=7(z+2)^6

and

f(z+3)=7(z+5)6.f'(z+3)=7(z+5)^6.
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