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Question 9.13

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TZ
leumasicOfficial

3 months ago

We have

limk0h(a+k)h(a)k=limk0f(a+k)f(a)k\lim_{k\to 0^-}\frac{h(a+k)-h(a)}{k}=\lim_{k\to 0^-}\frac{f(a+k)-f(a)}{k}

and

limk0+h(a+k)h(a)k=limk0+g(a+k)g(a)k.\lim_{k\to 0^+}\frac{h(a+k)-h(a)}{k}=\lim_{k\to 0^+}\frac{g(a+k)-g(a)}{k}.

Since both limits are equal, then hh is differentiable at aa.

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Q 9.13