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Question 9.4

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TZ
leumasicOfficial

3 months ago

Our conjecture is that Sn(x)=nxn1S_n'(x)=nx^{n-1}. Indeed,

Sn(x)=limh0Sn(x+h)Sn(x)h=limh0(x+h)nxnh=limh0i=0n(ni)xihnixnh=limh0i=0n1(ni)xihnih=limh0i=0n1(ni)xihn1i=n!(n1)!1!xn1=nxn1.\begin{align*} S_n'(x)&=\lim_{h\to 0}\frac{S_n(x+h)-S_n(x)}{h} \\ &=\lim_{h\to 0}\frac{(x+h)^n-x^n}{h} \\ &=\lim_{h\to 0}\frac{\sum_{i=0}^n {n\choose i}x^i h^{n-i}-x^n}{h} \\ &=\lim_{h\to 0}\frac{\sum_{i=0}^{n-1}{n\choose i}x^i h^{n-i}}{h} \\ &=\lim_{h\to 0}\sum_{i=0}^{n-1}{n\choose i}x^i h^{n-1-i} \\ &=\frac{n!}{(n-1)!1!}x^{n-1} \\ &=nx^{n-1}. \end{align*}
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Q 9.4

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Q 9.4