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Question 6.9

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TZ
leumasicOfficial

3 months ago

a) This is the negation of the definition of continuity.

b) The negation of the definition of continuity is:

ε>0, δ>0, xxa<δf(x)f(a)ε.\exists \varepsilon>0,\ \forall \delta>0,\ \exists x \quad |x-a|<\delta \land |f(x)-f(a)|\geq \varepsilon.

Unpacking the second inequality, we have

f(x)f(a)ε    f(x)ε+f(a),orf(a)f(x)ε    f(x)ε+f(a).\begin{align*} f(x)-f(a)\geq \varepsilon &\implies f(x)\geq \varepsilon+f(a),\\ \text{or}\qquad f(a)-f(x)\geq \varepsilon &\implies f(x)\leq -\varepsilon+f(a). \end{align*}
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Q 6.9

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Q 6.9