Question 11.13

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leumasicOfficial

2 months ago

Let $a \in (0, \infty)$ . It follows that

\begin{align*} (a - 1)^2 \ge 0 &\implies a^2 - 2a + 1 \ge 0 \\ &\implies a^2 + 1 \ge 2a \\ &\implies a + \frac{1}{a} \ge 2. \end{align*}

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Q 11.13

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Q 11.13