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Question 10.6

Solutions

TZ
leumasicOfficial

3 months ago

i)

f(x)=g(x+g(a))f'(x)=g'(x+g(a))

ii)

f(x)=g(xg(a))g(a)f'(x)=g'(x\cdot g(a))g(a)

iii)

f(x)=g(x+g(x))(1+g(x))f'(x)=g'(x+g(x))(1+g'(x))

iv)

f(x)=g(x)(xa)+g(x)f'(x)=g'(x)(x-a)+g(x)

v)

f(x)=g(a)f'(x)=g(a)

vi)

f(x)=g((x3)2),f(x)=g((x3)2)(2(x3)).f(x)=g((x-3)^2),\qquad f'(x)=g'((x-3)^2)(2(x-3)).
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Q 10.6

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Q 10.6